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Spectral Theorem

Let $H$ be a Hilbert Space, $B(H)$ the set of Bounded linear operators from $H$ to itself, and $\sigma(T)$ the Spectrum of $T$. Then if $T\in B(H)$ and $T$ is normal, there exists a unique resolution of the identity $E$ on the Borel subsets of $\sigma(T)$ which satisfies

\begin{displaymath}
T=\int_{\sigma(T)} \lambda\,dE(\lambda).
\end{displaymath}

Furthermore, every projection $E(\omega)$ Commutes with every $S\in B(H)$ which Commutes with $T$.


References

Rudin, W. Theorem 12.23 in Functional Analysis, 2nd ed. New York: McGraw-Hill, 1991.




© 1996-9 Eric W. Weisstein
1999-05-26