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Azimuthal Equidistant Projection

\begin{figure}\begin{center}\BoxedEPSF{maps/azeq.epsf scaled 500}\end{center}\end{figure}

An Azimuthal Projection which is neither equal-Area nor Conformal. Let $\phi_1$ and $\lambda_0$ be the Latitude and Longitude of the center of the projection, then the transformation equations are given by

$\displaystyle x$ $\textstyle =$ $\displaystyle k'\cos\phi\sin(\lambda-\lambda_0)$ (1)
$\displaystyle y$ $\textstyle =$ $\displaystyle k'[\cos\phi_1\sin\phi-\sin\phi_1\cos\phi\cos(\lambda-\lambda_0)].$ (2)

Here,
\begin{displaymath}
k'={c\over\sin c}
\end{displaymath} (3)

and
\begin{displaymath}
\cos c=\sin\phi_1\sin\phi+\cos\phi_1\cos\phi\cos(\lambda-\lambda_0),
\end{displaymath} (4)

where $c$ is the angular distance from the center. The inverse Formulas are
\begin{displaymath}
\phi=\sin^{-1}\left({\cos c\sin\phi_1+{y\sin c\cos\phi_1\over c}}\right)
\end{displaymath} (5)

and


\begin{displaymath}
\lambda=\cases{
\lambda_0+\tan^{-1}\left({x\sin c\over c\co...
...+\tan^{-1}\left({x\over y}\right)& for $\phi_1=-90^\circ$,\cr}
\end{displaymath} (6)

with the angular distance from the center given by
\begin{displaymath}
c=\sqrt{x^2+y^2}.
\end{displaymath} (7)


References

Snyder, J. P. Map Projections--A Working Manual. U. S. Geological Survey Professional Paper 1395. Washington, DC: U. S. Government Printing Office, pp. 191-202, 1987.




© 1996-9 Eric W. Weisstein
1999-05-25