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Worpitzky's Identity


\begin{displaymath}
x^n=\sum_{k=0}^{n-1} \left\langle{n\atop k}\right\rangle{}{n+k\choose n},
\end{displaymath}

where $\left\langle{n\atop k}\right\rangle{}$ is an Eulerian Number and ${n\choose k}$ is a Binomial Coefficient.




© 1996-9 Eric W. Weisstein
1999-05-26